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Title: Study the manipulation of given equation into an equivalent logic circuit
Page Link: Study the manipulation of given equation into an equivalent logic circuit -
Posted By: seminar class
Created at: Friday 13th of May 2011 06:37:09 PM
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Name– study of Boolean equations using the given ICs.
Aim – to study the manipulation of given equation into an equivalent logic circuit.
Apparatus – required ICs, circuit board, power supply +5V DC, LED, connecting wires, soldering iron, cutter etc.
Circuit diagram –
Draw the logic diagram of given equation (using basic gates only)
on left page of practical record book
with pin numbers of gates and output equation.


Pro ....etc

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Title: whirling of shafts ppt
Page Link: whirling of shafts ppt -
Posted By:
Created at: Wednesday 18th of September 2013 11:24:21 PM
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PLEASE I REQUST TO U GIVE ME A PPT OF WHIRLING SPEED OF SHAFT
....etc

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Title: PROGRAM TO FIND ROOTS OF QUADRATIC EQUATION BY USING PACKAGES AND INTERFACE
Page Link: PROGRAM TO FIND ROOTS OF QUADRATIC EQUATION BY USING PACKAGES AND INTERFACE -
Posted By: project topics
Created at: Wednesday 06th of April 2011 03:48:35 PM
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//QuadEqn.java
package p;
interface Quadratic
{
void process();
}
public class QuadEqn implements Quadratic
{
double a,b,c,d;
public QuadEqn(double x,double y,double z)
{
a=x;
b=y;
c=z;
}
public void process()
{

d=b*b-(4*a*c);
if(d==0)
{
double r=-b/2*a;
System.out.println(Roots are equal.Root=\t+r);
}
else
if(d>0)
{
double sq=Math.sqrt(d);
double r1=(-b+sq)/2*a;
double r2=(-b-sq)/2*a;
System.out.println(Root1=\t+r1+\nRoot2=\t+r2);
}
else
System.out.pri ....etc

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Title: design of shafts on the basis of rigidity and strength ppt
Page Link: design of shafts on the basis of rigidity and strength ppt -
Posted By:
Created at: Sunday 04th of November 2012 12:44:11 AM
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design of shafts on the basis of rigidity and strength ppt ....etc

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Title: SOLUTION OF DIFFERENCE EQUATION WITHOUT INITIAL CONDITIONS
Page Link: SOLUTION OF DIFFERENCE EQUATION WITHOUT INITIAL CONDITIONS -
Posted By: seminar class
Created at: Friday 06th of May 2011 06:05:41 PM
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Procedure:-
1. Rewrite the given difference equation to have only the output terms on the LHS and input terms to be on RHS
2. Create a Matrix of Y coefficients, a
3. Create a Matrix of X coefficients, b
4. Generate the input sequence x(n)
5. Find the output of the system for the input sequence x(n)
6. Plot the input and the output

MATLAB program for difference equation without initial condition
clear
close all
clc

% THE INPUT SEQUENCE IS X(N) = U(N)
% THE DIFFERENCE EQUATION IS Y(N) – 0.9Y(N-1)= X(N)
% N ....etc

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Title: DESIGNING OF SHAFTS
Page Link: DESIGNING OF SHAFTS -
Posted By: seminar surveyer
Created at: Wednesday 20th of October 2010 02:28:38 PM
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Prepared By;
Vivek Hayaran
Prahalad Yadav
Aniket Kumar




The shafts may be designed on the basis of -

-Strength
-Stiffness

Cases of designing of shafts, on the basis of Strength
(a) Shafts subjected to Twisting Moment only.
(b) Shafts subjected to Bending Moment only.
(c) Shafts subjected to Combined Twisting and Bending Moment only.
....etc

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Title: Shafts
Page Link: Shafts -
Posted By: seminar class
Created at: Tuesday 22nd of March 2011 03:01:21 PM
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Shafts:
Shafts are a rotating element which is used to transmit power from one place to another. The power is delivered to the shaft by some tangential force and the resultant torque (or twisting moment) set up within the shaft permits the power to be transferred to various members such as pulleys, gears etc are mounted on it. These members along with the forces exerted upon them causes the shaft to bending. In other words, we may say that a shaft is used for the transmission of torque and bending moment. The various ....etc

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Title: SOLUTION OF DIFFERENCE EQUATION WITH INITIAL CONDITIONS
Page Link: SOLUTION OF DIFFERENCE EQUATION WITH INITIAL CONDITIONS -
Posted By: seminar class
Created at: Friday 06th of May 2011 06:10:52 PM
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clear
close all
clc
% SOLVE THE GIVEN DIFFERENCE EQUATION Y(N) - 1.5Y(N-1) + 0.5Y(N-2) = X(N), N >= 0
% X(N) = (1/4)^n * U(N) SUBJECT TO Y(-1) = 4 AND Y(-2) = 10
% CALCULATE AND PLOT THE OUTPUT OF THE SYSTEM
% FIND THE TRANSFER FUNCTION OF THE GIVEN DIFFERENCE EQUATION H(Z) = Y(Z)/X(Z)
% NUMERATOR POLYNOMIAL IS a AND DENOMINATOR POLYNOMIAL IS b
% FOR THE ABOVE EXAMPLE b = AND a =

b = ;
a = ;
% FIND THE INITIAL CONDITIONS FOR THE INPUT X SUCH THAT THE GIVEN INITIAL CONDITIONS
% FOR Y ARE OBTAIN ....etc

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Title: Laplaces equation
Page Link: Laplaces equation -
Posted By: seminar surveyer
Created at: Thursday 23rd of December 2010 07:31:04 PM
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Submitted by:Isha



Introduction

Laplace's equation
Laplace's equation is a partial differential equation. Partial differential equations (PDE) are a type of differential equation, i.e., a relation involving an unknown function (or functions) of several independent variables and their partial derivatives with respect to those variables. Partial differential equations are used to formulate, and thus aid the solution of, problems involving functions of several variable ....etc

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Title: An Application of Structural Equation Modeling in Evaluating AccidentInjury Occurren
Page Link: An Application of Structural Equation Modeling in Evaluating AccidentInjury Occurren -
Posted By: seminar class
Created at: Wednesday 16th of March 2011 02:23:50 PM
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PRESENTED BY:
Dr J Maiti


An Application of Structural Equation Modeling in Evaluating Accident/Injury Occurrences in Underground Coal Mines
Introduction
 The purpose of this presentation is to show how Structural Equation Modeling (SEM) can be applied to real life problem solving.
Stages in SEM
• Stage 1: Developing a Theoretically Based
Model
• Stage 2: Constructing a Path Diagram of Causal Relationships
– Elements of a Path Diagram
– Examples of Path Diagrams ....etc

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