i need a matlab code for convolutional encoder using codetree, can u please help. ....etc

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Procedure:-
1. Read the input sequence, x and plot
2. Read the impulse response of the system, h and plot
3. Convolve the two results and plot them
Description:-
Linear Convolution involves the following operations.
1. Folding
2. Multiplication
3. Addition
4. Shifting
These operations can be represented by a Mathematical Expression as follows:
y =  xh

x= Input signal Samples
h= Impulse response co-efficient.
y= Convolution output.
n = No. of Input sample ....etc

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module multiplier_block (
X,
Y1,
Y2,
Y3,
Y4,
Y5,
Y6,
Y7,
Y8,
Y9,
Y10
);

// Port mode declarations:
input signed X;
output signed
Y1,
Y2,
Y3,
Y4,
Y5,
Y6,
Y7,
Y8,
Y9,
Y10;

wire Y ;

assign Y1 = Y;
assign Y2 = Y;
assign Y3 = Y;
assign Y4 = Y;
assign Y5 = Y;
assign Y6 = Y;
assign Y7 = Y;
assign Y8 = Y;
assign Y9 = Y;
assign Y10 = Y;

....etc

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The calculator is an extension of a mathematician and it has opened up new possibilities within mathematics. It is a machine though, and it is only capable of doing what it is programmed to do. Accordingly, this project aims to develop the internal programmed computational code in the form of a computer program that a scientific calculator could use to compute functions such as square root, the exponential, and sine functions.1 The idea of this project assumes that that the programmer has already developed the very basic addition, ....etc

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#include
#include
int m,n,x,h,y,i,j,temp,k,x2,a;
void main()
{
printf( enter the length of the first sequence\n);
scanf(%d,&m);
printf( enter the length of the second sequence\n);
scanf(%d,&n);
printf( enter the first sequence\n);
for(i=0;i scanf(%d,&x);
printf( enter the second sequence\n);
for(j=0;j scanf(%d,&h);
if(m-n!=0) /*If length of both sequences are not equal*/
{
if(m>n) /* Pad the smalle ....etc

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circular convolution of different length sequences ....etc

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/* prg to implement linear convolution */
#include
#include
int y;
main()
{ int m=6; /*Length of i/p samples sequence*/
int n=6; /*Length of impulse response Co-efficients */
int i=0,j;
int x={1,2,3,4,5,6,0,0,0,0,0,0}; /*Input Signal Samples*/
int h={1,2,3,4,5,6,0,0,0,0,0,0}; /*Impulse Response Co-efficients*/

for(i=0;i {
y=0;
for(j=0;j<=i;j++)
y+=x*h;
}
for(i=0;i printf(%d\n,y);
}

PROCEDURE:
 Open Code Compos ....etc

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Procedure:-
1) Find the length of the first sequence x=x_length
2) Find the length of the first sequence h=h_length
3) Take the circular convolution order as N
4) If x_length < N, pad enough number of zeros to x, so that the number of samples in the modified x=N
5) If h_length < N ,pad enough number of zeros to h, so that the number of samples in the modified h=N
6) Take DFT for modified x=x(k)
7) Take DFT for modified h=H(k)
8) Compute Y(K)=X(K)*H(K)
9) Compute y(n)=IDFT(Y(k))
10) Verify if y=conv(x, ....etc

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Procedure:-
1. Enter the sequence x
2. Enter the sequence y
3. Find the lengths of x and y,ie;Nx and Ny respectively
4. Check Nx=Ny:proceed if equal
5. Initialize a loop variable number of output points
6. For each out sample , access the samples of y in the cyclic order
7. Find the sum of products of x and cyclically folded and shifted y
Description:-
Steps for Cyclic Convolution
Steps for cyclic convolution are the same as the usual convolution, except all index calculations are done mod N = on ....etc

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Procedure:-
1) Find the length of the first sequence x=x_length
2) Find the length of the second sequence h=h_length
3) Estimate the number of samples in the result of linear convolution of x &h=Y_length
4) If X_length 5) If h_length 6) Take DFT for modified x=x(k)
7) Take DFT for modified h=H(k)
8) ....etc

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